2sin^2(2x)+5sin(2x)-3=0

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Solution for 2sin^2(2x)+5sin(2x)-3=0 equation:


Simplifying
2sin2(2x) + 5sin(2x) + -3 = 0

Remove parenthesis around (2x)
2in2s * 2x + 5sin(2x) + -3 = 0

Reorder the terms for easier multiplication:
2 * 2in2s * x + 5sin(2x) + -3 = 0

Multiply 2 * 2
4in2s * x + 5sin(2x) + -3 = 0

Multiply in2s * x
4in2sx + 5sin(2x) + -3 = 0

Remove parenthesis around (2x)
4in2sx + 5ins * 2x + -3 = 0

Reorder the terms for easier multiplication:
4in2sx + 5 * 2ins * x + -3 = 0

Multiply 5 * 2
4in2sx + 10ins * x + -3 = 0

Multiply ins * x
4in2sx + 10insx + -3 = 0

Reorder the terms:
-3 + 10insx + 4in2sx = 0

Solving
-3 + 10insx + 4in2sx = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 10insx + 3 + 4in2sx = 0 + 3

Reorder the terms:
-3 + 3 + 10insx + 4in2sx = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 10insx + 4in2sx = 0 + 3
10insx + 4in2sx = 0 + 3

Combine like terms: 0 + 3 = 3
10insx + 4in2sx = 3

Reorder the terms:
-3 + 10insx + 4in2sx = 3 + -3

Combine like terms: 3 + -3 = 0
-3 + 10insx + 4in2sx = 0

The solution to this equation could not be determined.

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